What are the solutions to the equation 8m^2-4=0 ?

The solutions to the equation 8m^2-4=0 are m= 1/(sqrt(2)),m=-1/(sqrt(2))

Find the zeros of 8m^2-4=0

The zeros of 8m^2-4=0 are m= 1/(sqrt(2)),m=-1/(sqrt(2))

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8 m^{2} - 4 = 0

m = \frac{1}{2}, m = - \frac{1}{2}

Decimal Notation

m = 0.70710 \dots, m = - 0.70710 \dots

Solution steps

8 m^{2} - 4 = 0

Move

4

to the right side

8 m^{2} = 4

Divide both sides by

8

m^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{1}{2}, m = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

m = \frac{1}{2}, m = - \frac{1}{2}

3 k^{3} + 24 k^{2} + 45 k

x^{2} - 2 \leq 1

x + 7 = 9

4 x^{2} - 2 x - 6

4 - (- 5)

What are the solutions to the equation 8m^2-4=0 ?
The solutions to the equation 8m^2-4=0 are m= 1/(sqrt(2)),m=-1/(sqrt(2))
Find the zeros of 8m^2-4=0
The zeros of 8m^2-4=0 are m= 1/(sqrt(2)),m=-1/(sqrt(2))