Solution
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For the solutions are
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The solutions to the quadratic equation are:
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Frequently Asked Questions (FAQ)
What are the solutions to the equation 49=(0+2)^2+(y-3)^2 ?
The solutions to the equation 49=(0+2)^2+(y-3)^2 are y=3sqrt(5)+3,y=-3sqrt(5)+3Find the zeros of 49=(0+2)^2+(y-3)^2
The zeros of 49=(0+2)^2+(y-3)^2 are y=3sqrt(5)+3,y=-3sqrt(5)+3