What is -3<= (4x+8)/3 <= 9 ?

The solution to -3<= (4x+8)/3 <= 9 is -17/4 <= x<= 19/4

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-3<= (4x+8)/3 <= 9

- 3 \leq \frac{4 x + 8}{3} \leq 9

- \frac{17}{4} \leq x \leq \frac{19}{4}

Interval Notation

[- \frac{17}{4}, \frac{19}{4}]

Decimal Notation

- 4.25 \leq x \leq 4.75

Solution steps

- 3 \leq \frac{4 x + 8}{3} \leq 9

a \leq u \leq b

then

a \leq u and u \leq b

- 3 \leq \frac{4 x + 8}{3} and \frac{4 x + 8}{3} \leq 9

- 3 \leq \frac{4 x + 8}{3} : x \geq - \frac{17}{4}

\frac{4 x + 8}{3} \leq 9 : x \leq \frac{19}{4}

Combine the intervals

x \geq - \frac{17}{4} and x \leq \frac{19}{4}

Merge Overlapping Intervals

- \frac{17}{4} \leq x \leq \frac{19}{4}

x + 3 = 12

x - \frac{1}{4} x = 15

2 x^{2} - 8 = 24

536

6 x - 8 = 0

What is -3<= (4x+8)/3 <= 9 ?
The solution to -3<= (4x+8)/3 <= 9 is -17/4 <= x<= 19/4