What is (9x+2)/(6x-5)<= 1 ?

The solution to (9x+2)/(6x-5)<= 1 is -7/3 <= x< 5/6

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(9x+2)/(6x-5)<= 1

\frac{9 x + 2}{6 x - 5} \leq 1

- \frac{7}{3} \leq x < \frac{5}{6}

Interval Notation

[- \frac{7}{3}, \frac{5}{6})

Decimal Notation

- 2.33333 \dots \leq x < 0.83333 \dots

Solution steps

\frac{9 x + 2}{6 x - 5} \leq 1

Rewrite in standard form

\frac{3 x + 7}{6 x - 5} \leq 0

Identify the intervals

- \frac{7}{3} \leq x < \frac{5}{6}

(x^{\frac{2}{3}})^{9}

\frac{8 !}{5 ! \cdot 3 !}

\frac{1}{3} \cdot \frac{3}{5}

- 4 = - 1 + \frac{x}{17}

\frac{1}{3} \frac{3}{4}