What are the solutions to the equation 16x^2+48x+37=0 ?

The solutions to the equation 16x^2+48x+37=0 are x=-3/2+i 1/4 ,x=-3/2-i 1/4

Find the zeros of 16x^2+48x+37=0

The zeros of 16x^2+48x+37=0 are x=-3/2+i 1/4 ,x=-3/2-i 1/4

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16 x^{2} + 48 x + 37 = 0

x = - \frac{3}{2} + i \frac{1}{4}, x = - \frac{3}{2} - i \frac{1}{4}

Solution steps

16 x^{2} + 48 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 16 \cdot 37}{2 \cdot 16}

Simplify

4 8^{2} - 4 \cdot 16 \cdot 37 : 8 i

x_{1, 2} = \frac{- 48 \pm 8 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 48 + 8 i}{2 \cdot 16}, x_{2} = \frac{- 48 - 8 i}{2 \cdot 16}

x = \frac{- 48 + 8 i}{2 \cdot 16} : - \frac{3}{2} + i \frac{1}{4}

x = \frac{- 48 - 8 i}{2 \cdot 16} : - \frac{3}{2} - i \frac{1}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{1}{4}, x = - \frac{3}{2} - i \frac{1}{4}

x + 5 < - 4

x^{2} + x - 72 = 0

10000 \cdot \frac{1}{( 1 + 0.12 ) ^{3}}

2 = \frac{1}{6} (10 x + 6)

x = 130 e^{0.05 \cdot 1}

What are the solutions to the equation 16x^2+48x+37=0 ?
The solutions to the equation 16x^2+48x+37=0 are x=-3/2+i 1/4 ,x=-3/2-i 1/4
Find the zeros of 16x^2+48x+37=0
The zeros of 16x^2+48x+37=0 are x=-3/2+i 1/4 ,x=-3/2-i 1/4