What are the solutions to the equation -2x^2+13x=15 ?

The solutions to the equation -2x^2+13x=15 are x= 3/2 ,x=5

Find the zeros of -2x^2+13x=15

The zeros of -2x^2+13x=15 are x= 3/2 ,x=5

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- 2 x^{2} + 13 x = 15

x = \frac{3}{2}, x = 5

Decimal Notation

x = 1.5, x = 5

Solution steps

- 2 x^{2} + 13 x = 15

Move

15

to the left side

- 2 x^{2} + 13 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 2 ) ( - 15 )}{2 ( - 2 )}

1 3^{2} - 4 (- 2) (- 15) = 7

x_{1, 2} = \frac{- 13 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 13 + 7}{2 ( - 2 )}, x_{2} = \frac{- 13 - 7}{2 ( - 2 )}

x = \frac{- 13 + 7}{2 ( - 2 )} : \frac{3}{2}

x = \frac{- 13 - 7}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 5

23 + 23

81 - \frac{81}{2}

0 = (x + 8)^{2} - 1

4 y - 15 = 29

\frac{81 x ^{2} - y ^{2}}{3 x + y}

What are the solutions to the equation -2x^2+13x=15 ?
The solutions to the equation -2x^2+13x=15 are x= 3/2 ,x=5
Find the zeros of -2x^2+13x=15
The zeros of -2x^2+13x=15 are x= 3/2 ,x=5