What are the solutions to the equation 2x^2+35=17x ?

The solutions to the equation 2x^2+35=17x are x=5,x= 7/2

Find the zeros of 2x^2+35=17x

The zeros of 2x^2+35=17x are x=5,x= 7/2

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2 x^{2} + 35 = 17 x

x = 5, x = \frac{7}{2}

Decimal Notation

x = 5, x = 3.5

Solution steps

2 x^{2} + 35 = 17 x

Move

17 x

to the left side

2 x^{2} + 35 - 17 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 17 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 35}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 35 = 3

x_{1, 2} = \frac{- ( - 17 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 3}{2 \cdot 2}

x = \frac{- ( - 17 ) + 3}{2 \cdot 2} : 5

x = \frac{- ( - 17 ) - 3}{2 \cdot 2} : \frac{7}{2}

The solutions to the quadratic equation are:

x = 5, x = \frac{7}{2}

5 z^{2} + 3 z

\frac{4 !}{1 ! 3 !}

x^{2} + 6 x - 7 \geq 0

- 3 x^{2} + 3

\frac{1}{1 - \frac{1}{3}}

What are the solutions to the equation 2x^2+35=17x ?
The solutions to the equation 2x^2+35=17x are x=5,x= 7/2
Find the zeros of 2x^2+35=17x
The zeros of 2x^2+35=17x are x=5,x= 7/2