What are the solutions to the equation x^2+9x+2=0 ?

The solutions to the equation x^2+9x+2=0 are x=(-9+sqrt(73))/2 ,x=(-9-sqrt(73))/2

Find the zeros of x^2+9x+2=0

The zeros of x^2+9x+2=0 are x=(-9+sqrt(73))/2 ,x=(-9-sqrt(73))/2

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x^{2} + 9 x + 2 = 0

x = \frac{- 9 + 73}{2}, x = \frac{- 9 - 73}{2}

Decimal Notation

x = - 0.22799 \dots, x = - 8.77200 \dots

Solution steps

x^{2} + 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 2 = 73

x_{1, 2} = \frac{- 9 \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 73}{2 \cdot 1}, x_{2} = \frac{- 9 - 73}{2 \cdot 1}

x = \frac{- 9 + 73}{2 \cdot 1} : \frac{- 9 + 73}{2}

x = \frac{- 9 - 73}{2 \cdot 1} : \frac{- 9 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 73}{2}, x = \frac{- 9 - 73}{2}

5 x^{2} + 36 x + 7

\frac{( \frac{π}{4} )}{2}

\frac{1 + \frac{2}{2}}{2}

1 + \frac{1}{5} \cdot (5 + \frac{3}{5} \cdot (1 - \frac{3}{4}) - \frac{4}{5})

x^{2} - 100

What are the solutions to the equation x^2+9x+2=0 ?
The solutions to the equation x^2+9x+2=0 are x=(-9+sqrt(73))/2 ,x=(-9-sqrt(73))/2
Find the zeros of x^2+9x+2=0
The zeros of x^2+9x+2=0 are x=(-9+sqrt(73))/2 ,x=(-9-sqrt(73))/2