What are the solutions to the equation x^2-2x-3/4 =0 ?

The solutions to the equation x^2-2x-3/4 =0 are x=(2+sqrt(7))/2 ,x=(2-sqrt(7))/2

Find the zeros of x^2-2x-3/4 =0

The zeros of x^2-2x-3/4 =0 are x=(2+sqrt(7))/2 ,x=(2-sqrt(7))/2

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x^{2} - 2 x - \frac{3}{4} = 0

x = \frac{2 + 7}{2}, x = \frac{2 - 7}{2}

Decimal Notation

x = 2.32287 \dots, x = - 0.32287 \dots

Solution steps

x^{2} - 2 x - \frac{3}{4} = 0

Multiply both sides by

4

4 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 3) = 47

x_{1, 2} = \frac{- ( - 8 ) \pm 4 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 7}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 7}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 7}{2 \cdot 4} : \frac{2 + 7}{2}

x = \frac{- ( - 8 ) - 4 7}{2 \cdot 4} : \frac{2 - 7}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 7}{2}, x = \frac{2 - 7}{2}

5 (\frac{1}{2})^{2}

(8)^{2} + (6)^{2}

2^{2} + 2^{2}

\frac{7 π}{2} \cdot \frac{180}{π}

y^{- 2}

What are the solutions to the equation x^2-2x-3/4 =0 ?
The solutions to the equation x^2-2x-3/4 =0 are x=(2+sqrt(7))/2 ,x=(2-sqrt(7))/2
Find the zeros of x^2-2x-3/4 =0
The zeros of x^2-2x-3/4 =0 are x=(2+sqrt(7))/2 ,x=(2-sqrt(7))/2