What are the solutions to the equation 3x^2+9x+2=0 ?

The solutions to the equation 3x^2+9x+2=0 are x=(-9+sqrt(57))/6 ,x=(-9-sqrt(57))/6

Find the zeros of 3x^2+9x+2=0

The zeros of 3x^2+9x+2=0 are x=(-9+sqrt(57))/6 ,x=(-9-sqrt(57))/6

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3 x^{2} + 9 x + 2 = 0

x = \frac{- 9 + 57}{6}, x = \frac{- 9 - 57}{6}

Decimal Notation

x = - 0.24169 \dots, x = - 2.75830 \dots

Solution steps

3 x^{2} + 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 2 = 57

x_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 57}{2 \cdot 3}, x_{2} = \frac{- 9 - 57}{2 \cdot 3}

x = \frac{- 9 + 57}{2 \cdot 3} : \frac{- 9 + 57}{6}

x = \frac{- 9 - 57}{2 \cdot 3} : \frac{- 9 - 57}{6}

The solutions to the quadratic equation are:

x = \frac{- 9 + 57}{6}, x = \frac{- 9 - 57}{6}

(x + 3) (x - 4) \leq 0

2 (y + 7) = 28

- 6 n + 21 = 12 n - 15

(3 x) (4 x) = 7 x

\frac{5 y}{8} - \frac{1}{4} = \frac{y - 1}{2}

What are the solutions to the equation 3x^2+9x+2=0 ?
The solutions to the equation 3x^2+9x+2=0 are x=(-9+sqrt(57))/6 ,x=(-9-sqrt(57))/6
Find the zeros of 3x^2+9x+2=0
The zeros of 3x^2+9x+2=0 are x=(-9+sqrt(57))/6 ,x=(-9-sqrt(57))/6