What are the solutions to the equation -0.05x^2+10x-200=0 ?

The solutions to the equation -0.05x^2+10x-200=0 are x=20(5-sqrt(15)),x=20(5+sqrt(15))

Find the zeros of -0.05x^2+10x-200=0

The zeros of -0.05x^2+10x-200=0 are x=20(5-sqrt(15)),x=20(5+sqrt(15))

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- 0.05 x^{2} + 10 x - 200 = 0

x = 20 (5 - 15), x = 20 (5 + 15)

Decimal Notation

x = 22.54033 \dots, x = 177.45966 \dots

Solution steps

- 0.05 x^{2} + 10 x - 200 = 0

Multiply both sides by

100

- 5 x^{2} + 1000 x - 20000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1000 \pm 100 0 ^{2} - 4 ( - 5 ) ( - 20000 )}{2 ( - 5 )}

100 0^{2} - 4 (- 5) (- 20000) = 20015

x_{1, 2} = \frac{- 1000 \pm 200 15}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1000 + 200 15}{2 ( - 5 )}, x_{2} = \frac{- 1000 - 200 15}{2 ( - 5 )}

x = \frac{- 1000 + 200 15}{2 ( - 5 )} : 20 (5 - 15)

x = \frac{- 1000 - 200 15}{2 ( - 5 )} : 20 (5 + 15)

The solutions to the quadratic equation are:

x = 20 (5 - 15), x = 20 (5 + 15)

\frac{6 x ^{4} y ^{7}}{12 x ^{5} y ^{- 8}}

\frac{5}{3} (4)^{2} - \frac{26}{3} (4) + x = - 8

6 x + 58 > 142

7 x - 8 \leq - 15

64 a^{7} b^{7} - a b^{13}

What are the solutions to the equation -0.05x^2+10x-200=0 ?
The solutions to the equation -0.05x^2+10x-200=0 are x=20(5-sqrt(15)),x=20(5+sqrt(15))
Find the zeros of -0.05x^2+10x-200=0
The zeros of -0.05x^2+10x-200=0 are x=20(5-sqrt(15)),x=20(5+sqrt(15))