What is (6x^4y^7)/(12x^5y^{-8)} ?

The solution to (6x^4y^7)/(12x^5y^{-8)} is (y^{15})/(2x)

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simplify (6x^4y^7)/(12x^5y^{-8)}

simplify

\frac{6 x ^{4} y ^{7}}{12 x ^{5} y ^{- 8}}

\frac{y ^{15}}{2 x}

Solution steps

\frac{6 x ^{4} y ^{7}}{12 x ^{5} y ^{- 8}}

Factor the number:

12 = 6 \cdot 2

= \frac{6 x ^{4} y ^{7}}{6 \cdot 2 x ^{5} y ^{- 8}}

Cancel the common factor:

6

= \frac{x ^{4} y ^{7}}{2 x ^{5} y ^{- 8}}

Simplify

\frac{y ^{7}}{y ^{- 8}} : y^{15}

= \frac{x ^{4} y ^{15}}{2 x ^{5}}

Simplify

\frac{x ^{4}}{x ^{5}} : \frac{1}{x}

= \frac{y ^{15}}{2 x}

\frac{5}{3} (4)^{2} - \frac{26}{3} (4) + x = - 8

6 x + 58 > 142

7 x - 8 \leq - 15

64 a^{7} b^{7} - a b^{13}

26 p - 20 > 14 p + 64

What is (6x^4y^7)/(12x^5y^{-8)} ?
The solution to (6x^4y^7)/(12x^5y^{-8)} is (y^{15})/(2x)