What is (x^2-y^2)/(3x)*(3y)/(x+y) ?

The solution to (x^2-y^2)/(3x)*(3y)/(x+y) is ((x-y)y)/x

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simplify (x^2-y^2)/(3x)*(3y)/(x+y)

simplify

\frac{x ^{2} - y ^{2}}{3 x} \cdot \frac{3 y}{x + y}

\frac{( x - y ) y}{x}

Solution steps

\frac{x ^{2} - y ^{2}}{3 x} \cdot \frac{3 y}{x + y}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x ^{2} - y ^{2} ) \cdot 3 y}{3 x ( x + y )}

Cancel the common factor:

3

= \frac{( x ^{2} - y ^{2} ) y}{x ( x + y )}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

x^{2} - y^{2} = (x + y) (x - y)

= \frac{( x + y ) ( x - y ) y}{x ( x + y )}

Cancel the common factor:

x + y

= \frac{( x - y ) y}{x}

x^{2} < 3 - 2 x

\frac{( 2 x + 1 )}{6} - \frac{( x - 3 )}{3} = \frac{( 4 x - 1 )}{3} + \frac{( x - 6 )}{2}

\frac{t}{11} = - 5

1 0^{2 l o g_{10} (5)}

- 5 x \geq - 9

What is (x^2-y^2)/(3x)*(3y)/(x+y) ?
The solution to (x^2-y^2)/(3x)*(3y)/(x+y) is ((x-y)y)/x