What are the solutions to the equation (3z-18)^2+59=14 ?

The solutions to the equation (3z-18)^2+59=14 are z=sqrt(5)i+6,z=-sqrt(5)i+6

Find the zeros of (3z-18)^2+59=14

The zeros of (3z-18)^2+59=14 are z=sqrt(5)i+6,z=-sqrt(5)i+6

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(3 z - 18)^{2} + 59 = 14

z = 5 i + 6, z = - 5 i + 6

Solution steps

(3 z - 18)^{2} + 59 = 14

Move

59

to the right side

(3 z - 18)^{2} = - 45

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 z - 18 = - 45 : z = 5 i + 6

Solve

3 z - 18 = - - 45 : z = - 5 i + 6

The solutions to the quadratic equation are:

z = 5 i + 6, z = - 5 i + 6

\frac{3 ( x - 5 )}{4} - x = 1 - \frac{x}{6}

32 < \frac{h}{13} + 33

- \frac{x}{8} = 5

\frac{4}{5} + \frac{2}{10}

x^{2} + 20 x + 100 = 0

What are the solutions to the equation (3z-18)^2+59=14 ?
The solutions to the equation (3z-18)^2+59=14 are z=sqrt(5)i+6,z=-sqrt(5)i+6
Find the zeros of (3z-18)^2+59=14
The zeros of (3z-18)^2+59=14 are z=sqrt(5)i+6,z=-sqrt(5)i+6