What are the solutions to the equation n^2+10n-47=0 ?

The solutions to the equation n^2+10n-47=0 are n=-5+6sqrt(2),n=-5-6sqrt(2)

Find the zeros of n^2+10n-47=0

The zeros of n^2+10n-47=0 are n=-5+6sqrt(2),n=-5-6sqrt(2)

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n^{2} + 10 n - 47 = 0

n = - 5 + 62, n = - 5 - 62

Decimal Notation

n = 3.48528 \dots, n = - 13.48528 \dots

Solution steps

n^{2} + 10 n - 47 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 47 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 47) = 122

n_{1, 2} = \frac{- 10 \pm 12 2}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 10 + 12 2}{2 \cdot 1}, n_{2} = \frac{- 10 - 12 2}{2 \cdot 1}

n = \frac{- 10 + 12 2}{2 \cdot 1} : - 5 + 62

n = \frac{- 10 - 12 2}{2 \cdot 1} : - 5 - 62

The solutions to the quadratic equation are:

n = - 5 + 62, n = - 5 - 62

18 - \frac{2}{3} (6 x - 12) = 4 x + 2

6 x + 5 = 0

3 a^{2} - 45 ab + 150 b^{2}

- \frac{8}{17}

What are the solutions to the equation n^2+10n-47=0 ?
The solutions to the equation n^2+10n-47=0 are n=-5+6sqrt(2),n=-5-6sqrt(2)
Find the zeros of n^2+10n-47=0
The zeros of n^2+10n-47=0 are n=-5+6sqrt(2),n=-5-6sqrt(2)