What are the solutions to the equation 4x^2-4x+1=9 ?

The solutions to the equation 4x^2-4x+1=9 are x=2,x=-1

Find the zeros of 4x^2-4x+1=9

The zeros of 4x^2-4x+1=9 are x=2,x=-1

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4 x^{2} - 4 x + 1 = 9

x = 2, x = - 1

Solution steps

4 x^{2} - 4 x + 1 = 9

Move

9

to the left side

4 x^{2} - 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 8 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 8) = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 4}

x = \frac{- ( - 4 ) + 12}{2 \cdot 4} : 2

x = \frac{- ( - 4 ) - 12}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

x^{2} - 9 y^{2}

\frac{5}{- 3 i}

n^{5}

24 x^{3} y^{2} - 18 x y^{3} + 12 y^{3}

x^{2} + 4 = 9

What are the solutions to the equation 4x^2-4x+1=9 ?
The solutions to the equation 4x^2-4x+1=9 are x=2,x=-1
Find the zeros of 4x^2-4x+1=9
The zeros of 4x^2-4x+1=9 are x=2,x=-1