What is log_{49}(7)+log_{243}(27)-log_{25}(125) ?

The solution to log_{49}(7)+log_{243}(27)-log_{25}(125) is -2/5

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simplify log_{49}(7)+log_{243}(27)-log_{25}(125)

simplify

lo g_{49} (7) + lo g_{243} (27) - lo g_{25} (125)

- \frac{2}{5}

Decimal Notation

- 0.4

Solution steps

lo g_{49} (7) + lo g_{243} (27) - lo g_{25} (125)

lo g_{49} (7) = \frac{1}{2}

lo g_{243} (27) = \frac{3}{5}

lo g_{25} (125) = \frac{3}{2}

= \frac{1}{2} + \frac{3}{5} - \frac{3}{2}

\frac{1}{2} + \frac{3}{5} - \frac{3}{2} = - \frac{2}{5}

= - \frac{2}{5}

2 x^{3} - 8 x^{2} > 0

18 n^{4} - 30 n^{2} p + 50 p^{2}

3 n^{2} - 6 n + 3

5 x + 15 (6) = 30

lo g_{5} (\frac{4}{7})

What is log_{49}(7)+log_{243}(27)-log_{25}(125) ?
The solution to log_{49}(7)+log_{243}(27)-log_{25}(125) is -2/5