What are the solutions to the equation n^2-4n=0 ?

The solutions to the equation n^2-4n=0 are n=4,n=0

Find the zeros of n^2-4n=0

The zeros of n^2-4n=0 are n=4,n=0

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n^{2} - 4 n = 0

n = 4, n = 0

Solution steps

n^{2} - 4 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

n_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, n_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

n = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

n = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

n = 4, n = 0

x + 8 = 4

x (x + 1) = x^{2} + 2 x + 3

x^{\frac{7}{4}}

4 (\frac{1}{2})^{4}

a + 3 a + 8 = 2 a + 10

What are the solutions to the equation n^2-4n=0 ?
The solutions to the equation n^2-4n=0 are n=4,n=0
Find the zeros of n^2-4n=0
The zeros of n^2-4n=0 are n=4,n=0