What are the solutions to the equation x^2-10x-49=7 ?

The solutions to the equation x^2-10x-49=7 are x=14,x=-4

Find the zeros of x^2-10x-49=7

The zeros of x^2-10x-49=7 are x=14,x=-4

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x^{2} - 10 x - 49 = 7

x = 14, x = - 4

Solution steps

x^{2} - 10 x - 49 = 7

Move

7

to the left side

x^{2} - 10 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 56) = 18

x_{1, 2} = \frac{- ( - 10 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 18}{2 \cdot 1}

x = \frac{- ( - 10 ) + 18}{2 \cdot 1} : 14

x = \frac{- ( - 10 ) - 18}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 14, x = - 4

6 x^{2} + 150 = 0

x^{4} - 2 x^{2} - 63

- 0.13633 (x)^{2} - 3.00066 (x) + 73.59566 = 24.91

10 x - 4 (x + 1) \geq 13 + 3 x

5 x^{2} - 13 x y + 6 y^{2}

What are the solutions to the equation x^2-10x-49=7 ?
The solutions to the equation x^2-10x-49=7 are x=14,x=-4
Find the zeros of x^2-10x-49=7
The zeros of x^2-10x-49=7 are x=14,x=-4