What are the solutions to the equation 6x^2+7x=3 ?

The solutions to the equation 6x^2+7x=3 are x= 1/3 ,x=-3/2

Find the zeros of 6x^2+7x=3

The zeros of 6x^2+7x=3 are x= 1/3 ,x=-3/2

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6 x^{2} + 7 x = 3

x = \frac{1}{3}, x = - \frac{3}{2}

Decimal Notation

x = 0.33333 \dots, x = - 1.5

Solution steps

6 x^{2} + 7 x = 3

Move

3

to the left side

6 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 3) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 6}, x_{2} = \frac{- 7 - 11}{2 \cdot 6}

x = \frac{- 7 + 11}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 7 - 11}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{2}

\frac{x}{2} + \frac{x}{3} > 5

12 n^{2} + 7 n^{3}

- 6 - (- 8)

(- \frac{2}{3})^{- 5}

x^{2} = 1 - x^{2}

What are the solutions to the equation 6x^2+7x=3 ?
The solutions to the equation 6x^2+7x=3 are x= 1/3 ,x=-3/2
Find the zeros of 6x^2+7x=3
The zeros of 6x^2+7x=3 are x= 1/3 ,x=-3/2