What is the answer to -3(x-1)=2[x-4(x-2)+x] ?

The answer to -3(x-1)=2[x-4(x-2)+x] is x=13

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-3(x-1)=2[x-4(x-2)+x]

- 3 (x - 1) = 2 [x - 4 (x - 2) + x]

x = 13

Solution steps

- 3 (x - 1) = 2 [x - 4 (x - 2) + x]

Expand

- 3 (x - 1) : - 3 x + 3

Expand

2 (x - 4 (x - 2) + x) : - 4 x + 16

- 3 x + 3 = - 4 x + 16

Move

3

to the right side

- 3 x = - 4 x + 13

Move

4 x

to the left side

x = 13

(x) = - x^{2} + 3

\frac{x}{x - 3} \geq 0

- 2 x + 2 = - 6

(- \frac{w ^{3}}{6})^{- 2}

3 (x - 2) + 4 = 3 x - 2

What is the answer to -3(x-1)=2[x-4(x-2)+x] ?
The answer to -3(x-1)=2[x-4(x-2)+x] is x=13
Solve for x: -3(x-1)=2[x-4(x-2)+x]
The solution is x=13