What are the solutions to the equation -9x^2+18x=16 ?

The solutions to the equation -9x^2+18x=16 are x=1-i(sqrt(7))/3 ,x=1+i(sqrt(7))/3

Find the zeros of -9x^2+18x=16

The zeros of -9x^2+18x=16 are x=1-i(sqrt(7))/3 ,x=1+i(sqrt(7))/3

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- 9 x^{2} + 18 x = 16

x = 1 - i \frac{7}{3}, x = 1 + i \frac{7}{3}

Solution steps

- 9 x^{2} + 18 x = 16

Move

16

to the left side

- 9 x^{2} + 18 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 9 ) ( - 16 )}{2 ( - 9 )}

Simplify

1 8^{2} - 4 (- 9) (- 16) : 67 i

x_{1, 2} = \frac{- 18 \pm 6 7 i}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 18 + 6 7 i}{2 ( - 9 )}, x_{2} = \frac{- 18 - 6 7 i}{2 ( - 9 )}

x = \frac{- 18 + 6 7 i}{2 ( - 9 )} : 1 - i \frac{7}{3}

x = \frac{- 18 - 6 7 i}{2 ( - 9 )} : 1 + i \frac{7}{3}

The solutions to the quadratic equation are:

x = 1 - i \frac{7}{3}, x = 1 + i \frac{7}{3}

(3 x + 2) (x + 1) = 1

y + x^{3} y^{4}

15 x^{2} - 34 x + 15

\frac{24 a ^{2} c ^{2}}{36 a c}

7 x^{2} = 49

What are the solutions to the equation -9x^2+18x=16 ?
The solutions to the equation -9x^2+18x=16 are x=1-i(sqrt(7))/3 ,x=1+i(sqrt(7))/3
Find the zeros of -9x^2+18x=16
The zeros of -9x^2+18x=16 are x=1-i(sqrt(7))/3 ,x=1+i(sqrt(7))/3