What are the solutions to the equation 4x^2-9x-1=0 ?

The solutions to the equation 4x^2-9x-1=0 are x=(9+sqrt(97))/8 ,x=(9-sqrt(97))/8

Find the zeros of 4x^2-9x-1=0

The zeros of 4x^2-9x-1=0 are x=(9+sqrt(97))/8 ,x=(9-sqrt(97))/8

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4 x^{2} - 9 x - 1 = 0

x = \frac{9 + 97}{8}, x = \frac{9 - 97}{8}

Decimal Notation

x = 2.35610 \dots, x = - 0.10610 \dots

Solution steps

4 x^{2} - 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 1) = 97

x_{1, 2} = \frac{- ( - 9 ) \pm 97}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 97}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 97}{2 \cdot 4}

x = \frac{- ( - 9 ) + 97}{2 \cdot 4} : \frac{9 + 97}{8}

x = \frac{- ( - 9 ) - 97}{2 \cdot 4} : \frac{9 - 97}{8}

The solutions to the quadratic equation are:

x = \frac{9 + 97}{8}, x = \frac{9 - 97}{8}

(\frac{1 - x}{2})^{2}

7 - 2 (1 - x) > 5 + 3 (x - 2)

(w^{3})^{3}

(3 x - 1) (x + 1) \geq x (2 x - 3) - 5

15 = c - 6

What are the solutions to the equation 4x^2-9x-1=0 ?
The solutions to the equation 4x^2-9x-1=0 are x=(9+sqrt(97))/8 ,x=(9-sqrt(97))/8
Find the zeros of 4x^2-9x-1=0
The zeros of 4x^2-9x-1=0 are x=(9+sqrt(97))/8 ,x=(9-sqrt(97))/8