What are the solutions to the equation 3y^2-2y-8=0 ?

The solutions to the equation 3y^2-2y-8=0 are y=2,y=-4/3

Find the zeros of 3y^2-2y-8=0

The zeros of 3y^2-2y-8=0 are y=2,y=-4/3

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3 y^{2} - 2 y - 8 = 0

y = 2, y = - \frac{4}{3}

Decimal Notation

y = 2, y = - 1.33333 \dots

Solution steps

3 y^{2} - 2 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 8) = 10

y_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 3}, y_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 3}

y = \frac{- ( - 2 ) + 10}{2 \cdot 3} : 2

y = \frac{- ( - 2 ) - 10}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

y = 2, y = - \frac{4}{3}

\frac{1}{9} + 1

10 = 31.9131246 x + 10.7438939

i^{6}

x + 3 > - 2

72 9^{- \frac{5}{6}}

What are the solutions to the equation 3y^2-2y-8=0 ?
The solutions to the equation 3y^2-2y-8=0 are y=2,y=-4/3
Find the zeros of 3y^2-2y-8=0
The zeros of 3y^2-2y-8=0 are y=2,y=-4/3