What is (x-1)/(x+6)>= (x-2)/(x+4) ?

The solution to (x-1)/(x+6)>= (x-2)/(x+4) is x<-6\lor-4<x<= 8

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(x-1)/(x+6)>= (x-2)/(x+4)

\frac{x - 1}{x + 6} \geq \frac{x - 2}{x + 4}

x < - 6 or - 4 < x \leq 8

Interval Notation

(- \infty, - 6) \cup (- 4, 8]

Solution steps

\frac{x - 1}{x + 6} \geq \frac{x - 2}{x + 4}

Rewrite in standard form

\frac{- x + 8}{( x + 6 ) ( x + 4 )} \geq 0

Identify the intervals

x < - 6 or - 4 < x \leq 8

3 x^{4} - 3

5 x - 4 \leq - 3 or 4 x + 6 > 0

(x + 10) (x - 2) = 0

- \frac{7}{8} \cdot (- \frac{7}{5})

\frac{5}{2} x - \frac{7}{6} x + \frac{11}{12} = \frac{47}{12}

What is (x-1)/(x+6)>= (x-2)/(x+4) ?
The solution to (x-1)/(x+6)>= (x-2)/(x+4) is x<-6\lor-4<x<= 8