What are the solutions to the equation x^2-169x+3600=0 ?

The solutions to the equation x^2-169x+3600=0 are x=144,x=25

Find the zeros of x^2-169x+3600=0

The zeros of x^2-169x+3600=0 are x=144,x=25

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x^{2} - 169 x + 3600 = 0

x = 144, x = 25

Solution steps

x^{2} - 169 x + 3600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 169 ) \pm ( - 169 ) ^{2} - 4 \cdot 1 \cdot 3600}{2 \cdot 1}

(- 169)^{2} - 4 \cdot 1 \cdot 3600 = 119

x_{1, 2} = \frac{- ( - 169 ) \pm 119}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 169 ) + 119}{2 \cdot 1}, x_{2} = \frac{- ( - 169 ) - 119}{2 \cdot 1}

x = \frac{- ( - 169 ) + 119}{2 \cdot 1} : 144

x = \frac{- ( - 169 ) - 119}{2 \cdot 1} : 25

The solutions to the quadratic equation are:

x = 144, x = 25

10 - 6 q < - 23

27 - \frac{1}{125} x^{3}

5 x^{2} + 33 x - 14 = 0

λ^{2} - 4 λ + 15 = 0

What are the solutions to the equation x^2-169x+3600=0 ?
The solutions to the equation x^2-169x+3600=0 are x=144,x=25
Find the zeros of x^2-169x+3600=0
The zeros of x^2-169x+3600=0 are x=144,x=25