What are the solutions to the equation -2x^2-7x+4=0 ?

The solutions to the equation -2x^2-7x+4=0 are x=-4,x= 1/2

Find the zeros of -2x^2-7x+4=0

The zeros of -2x^2-7x+4=0 are x=-4,x= 1/2

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- 2 x^{2} - 7 x + 4 = 0

x = - 4, x = \frac{1}{2}

Decimal Notation

x = - 4, x = 0.5

Solution steps

- 2 x^{2} - 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

(- 7)^{2} - 4 (- 2) \cdot 4 = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 ( - 2 )}, x_{2} = \frac{- ( - 7 ) - 9}{2 ( - 2 )}

x = \frac{- ( - 7 ) + 9}{2 ( - 2 )} : - 4

x = \frac{- ( - 7 ) - 9}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - 4, x = \frac{1}{2}

(\frac{5}{3} - 1) \cdot (\frac{7}{2} - 2)

\frac{6 x ^{2} - 17 x + 12}{4 x ^{2} + 2 x - 12} \leq 0

j^{2} - 10 j + 9

\frac{1}{i ^{2}}

- 2 x^{2} - 5 x - 4 = 0

What are the solutions to the equation -2x^2-7x+4=0 ?
The solutions to the equation -2x^2-7x+4=0 are x=-4,x= 1/2
Find the zeros of -2x^2-7x+4=0
The zeros of -2x^2-7x+4=0 are x=-4,x= 1/2