What is 2<= (4x+2/(-3))<= 10 ?

The solution to 2<= (4x+2/(-3))<= 10 is 2/3 <= x<= 8/3

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2<= (4x+2/(-3))<= 10

2 \leq (4 x + \frac{2}{- 3}) \leq 10

\frac{2}{3} \leq x \leq \frac{8}{3}

Interval Notation

[\frac{2}{3}, \frac{8}{3}]

Decimal Notation

0.66666 \dots \leq x \leq 2.66666 \dots

Solution steps

2 \leq (4 x + \frac{2}{- 3}) \leq 10

a \leq u \leq b

then

a \leq u and u \leq b

2 \leq (4 x + \frac{2}{- 3}) and (4 x + \frac{2}{- 3}) \leq 10

2 \leq 4 x + \frac{2}{- 3} : x \geq \frac{2}{3}

4 x + \frac{2}{- 3} \leq 10 : x \leq \frac{8}{3}

Combine the intervals

x \geq \frac{2}{3} and x \leq \frac{8}{3}

Merge Overlapping Intervals

\frac{2}{3} \leq x \leq \frac{8}{3}

3 x^{2} - 16 x + 21 = 0

∣ 4 v - 9 ∣ \leq 27

\frac{3 x ^{3} - 4 x ^{2} - 3 x - 2}{( x ) ( x - 1 )} < 0

x + 4 \leq 8

- \frac{x}{4} = 12

What is 2<= (4x+2/(-3))<= 10 ?
The solution to 2<= (4x+2/(-3))<= 10 is 2/3 <= x<= 8/3