What is the answer to (7k-3)/4 =(13-5k)/8 ?

The answer to (7k-3)/4 =(13-5k)/8 is k=1

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(7k-3)/4 =(13-5k)/8

\frac{7 k - 3}{4} = \frac{13 - 5 k}{8}

k = 1

Solution steps

\frac{7 k - 3}{4} = \frac{13 - 5 k}{8}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(7 k - 3) \cdot 8 = 4 (13 - 5 k)

Expand

(7 k - 3) \cdot 8 : 56 k - 24

Expand

4 (13 - 5 k) : 52 - 20 k

56 k - 24 = 52 - 20 k

Move

24

to the right side

56 k = - 20 k + 76

Move

20 k

to the left side

76 k = 76

Divide both sides by

76

k = 1

- 17 - \frac{1}{3} x \geq 4

498 + 150 - 232

4 x^{2} + 9 x y - 9 y^{2}

3 x - 15 \geq 3

- \frac{4}{7 i}

What is the answer to (7k-3)/4 =(13-5k)/8 ?
The answer to (7k-3)/4 =(13-5k)/8 is k=1
Solve for k: (7k-3)/4 =(13-5k)/8
The solution is k=1