What are the solutions to the equation 2p^2+7p-7=0 ?

The solutions to the equation 2p^2+7p-7=0 are p=(-7+sqrt(105))/4 ,p=(-7-sqrt(105))/4

Find the zeros of 2p^2+7p-7=0

The zeros of 2p^2+7p-7=0 are p=(-7+sqrt(105))/4 ,p=(-7-sqrt(105))/4

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2 p^{2} + 7 p - 7 = 0

p = \frac{- 7 + 105}{4}, p = \frac{- 7 - 105}{4}

Decimal Notation

p = 0.81173 \dots, p = - 4.31173 \dots

Solution steps

2 p^{2} + 7 p - 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 7) = 105

p_{1, 2} = \frac{- 7 \pm 105}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 7 + 105}{2 \cdot 2}, p_{2} = \frac{- 7 - 105}{2 \cdot 2}

p = \frac{- 7 + 105}{2 \cdot 2} : \frac{- 7 + 105}{4}

p = \frac{- 7 - 105}{2 \cdot 2} : \frac{- 7 - 105}{4}

The solutions to the quadratic equation are:

p = \frac{- 7 + 105}{4}, p = \frac{- 7 - 105}{4}

- 19 = - \frac{2}{3} x

2 (y - 1) + 4 y = 3 (y - 1) + 7

17 \cdot 5

9 \cdot 49 \cdot 16 + 57 - 3 \cdot \frac{5}{60}

\frac{5}{8} - \frac{3}{8}

What are the solutions to the equation 2p^2+7p-7=0 ?
The solutions to the equation 2p^2+7p-7=0 are p=(-7+sqrt(105))/4 ,p=(-7-sqrt(105))/4
Find the zeros of 2p^2+7p-7=0
The zeros of 2p^2+7p-7=0 are p=(-7+sqrt(105))/4 ,p=(-7-sqrt(105))/4