What are the solutions to the equation 10x^2+2=282 ?

The solutions to the equation 10x^2+2=282 are x=2sqrt(7),x=-2sqrt(7)

Find the zeros of 10x^2+2=282

The zeros of 10x^2+2=282 are x=2sqrt(7),x=-2sqrt(7)

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10 x^{2} + 2 = 282

x = 27, x = - 27

Decimal Notation

x = 5.29150 \dots, x = - 5.29150 \dots

Solution steps

10 x^{2} + 2 = 282

Move

2

to the right side

10 x^{2} = 280

Divide both sides by

10

x^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 28, x = - 28

28 = 27

- 28 = - 27

x = 27, x = - 27

\frac{1}{3} x + 10 = 55

\frac{1 - ( 2 + 3 i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}}

\frac{3}{4} = \frac{x}{9}

\frac{4}{6} + \frac{1}{3}

lo g_{9} (81) = L

What are the solutions to the equation 10x^2+2=282 ?
The solutions to the equation 10x^2+2=282 are x=2sqrt(7),x=-2sqrt(7)
Find the zeros of 10x^2+2=282
The zeros of 10x^2+2=282 are x=2sqrt(7),x=-2sqrt(7)