What are the solutions to the equation 4=-3x^2-11x ?

The solutions to the equation 4=-3x^2-11x are x=-(11+sqrt(73))/6 ,x=-(11-sqrt(73))/6

Find the zeros of 4=-3x^2-11x

The zeros of 4=-3x^2-11x are x=-(11+sqrt(73))/6 ,x=-(11-sqrt(73))/6

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4 = - 3 x^{2} - 11 x

x = - \frac{11 + 73}{6}, x = - \frac{11 - 73}{6}

Decimal Notation

x = - 3.25733 \dots, x = - 0.40933 \dots

Solution steps

4 = - 3 x^{2} - 11 x

Switch sides

- 3 x^{2} - 11 x = 4

Move

4

to the left side

- 3 x^{2} - 11 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 3 ) ( - 4 )}{2 ( - 3 )}

(- 11)^{2} - 4 (- 3) (- 4) = 73

x_{1, 2} = \frac{- ( - 11 ) \pm 73}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 73}{2 ( - 3 )}, x_{2} = \frac{- ( - 11 ) - 73}{2 ( - 3 )}

x = \frac{- ( - 11 ) + 73}{2 ( - 3 )} : - \frac{11 + 73}{6}

x = \frac{- ( - 11 ) - 73}{2 ( - 3 )} : - \frac{11 - 73}{6}

The solutions to the quadratic equation are:

x = - \frac{11 + 73}{6}, x = - \frac{11 - 73}{6}

5 x - 5 > 15

4 x^{- 3}

\frac{15 - 5 x}{6} - \frac{x - 4}{2} \geq \frac{2 x - 3}{3} - \frac{x}{1}

\frac{1 + i 2}{2} - (1 - i \frac{1}{2})

\frac{5 - x}{2} = 2 x - 7

What are the solutions to the equation 4=-3x^2-11x ?
The solutions to the equation 4=-3x^2-11x are x=-(11+sqrt(73))/6 ,x=-(11-sqrt(73))/6
Find the zeros of 4=-3x^2-11x
The zeros of 4=-3x^2-11x are x=-(11+sqrt(73))/6 ,x=-(11-sqrt(73))/6