What are the solutions to the equation 6+2x^2-3x=8x^2 ?

The solutions to the equation 6+2x^2-3x=8x^2 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

Find the zeros of 6+2x^2-3x=8x^2

The zeros of 6+2x^2-3x=8x^2 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

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6 + 2 x^{2} - 3 x = 8 x^{2}

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

Decimal Notation

x = - 1.28077 \dots, x = 0.78077 \dots

Solution steps

6 + 2 x^{2} - 3 x = 8 x^{2}

Move

8 x^{2}

to the left side

- 6 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 6 ) \cdot 6}{2 ( - 6 )}

(- 3)^{2} - 4 (- 6) \cdot 6 = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )}

x = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )} : - \frac{1 + 17}{4}

x = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )} : \frac{17 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

\frac{- 24 a ^{8}}{- 6 a ^{5}}

49 x^{2} + 84 x + 36

- 2 ∣ 3 x + 5 ∣ - 10 = - 18

b = \frac{13}{908} - \frac{5}{25} \cdot 908

4 x^{2} - 11 = 0

What are the solutions to the equation 6+2x^2-3x=8x^2 ?
The solutions to the equation 6+2x^2-3x=8x^2 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4
Find the zeros of 6+2x^2-3x=8x^2
The zeros of 6+2x^2-3x=8x^2 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4