What is (7xy^4)/(35x^2y^3) ?

The solution to (7xy^4)/(35x^2y^3) is y/(5x)

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simplify (7xy^4)/(35x^2y^3)

simplify

\frac{7 x y ^{4}}{35 x ^{2} y ^{3}}

\frac{y}{5 x}

Solution steps

\frac{7 x y ^{4}}{35 x ^{2} y ^{3}}

Factor the number:

35 = 7 \cdot 5

= \frac{7 x y ^{4}}{7 \cdot 5 x ^{2} y ^{3}}

Cancel the common factor:

7

= \frac{x y ^{4}}{5 x ^{2} y ^{3}}

Simplify

\frac{y ^{4}}{y ^{3}} : y

= \frac{x y}{5 x ^{2}}

Simplify

\frac{x}{x ^{2}} : \frac{1}{x}

= \frac{y}{5 x}

1 - 64 b^{3}

2 \geq \frac{8 + x}{11}

5 (11 x - 18) = 3 (2 x + 7)

- 7 x^{2} - 11 x - 4

15 x^{4} - 27 x^{3} y - 6 x^{2} y^{2}