What are the solutions to the equation 1.87=4.9t^2 ?

The solutions to the equation 1.87=4.9t^2 are t=(sqrt(187))/(7sqrt(10)),t=-(sqrt(187))/(7sqrt(10))

Find the zeros of 1.87=4.9t^2

The zeros of 1.87=4.9t^2 are t=(sqrt(187))/(7sqrt(10)),t=-(sqrt(187))/(7sqrt(10))

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1.87 = 4.9 t^{2}

t = \frac{187}{7 10}, t = - \frac{187}{7 10}

Decimal Notation

t = 0.61776 \dots, t = - 0.61776 \dots

Solution steps

1.87 = 4.9 t^{2}

Switch sides

4.9 t^{2} = 1.87

Multiply both sides by

100

490 t^{2} = 187

Divide both sides by

490

t^{2} = \frac{187}{490}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{187}{490}, t = - \frac{187}{490}

\frac{187}{490} = \frac{187}{7 10}

- \frac{187}{490} = - \frac{187}{7 10}

t = \frac{187}{7 10}, t = - \frac{187}{7 10}

3 6^{- \frac{1}{2}}

x^{7} \cdot x^{3}

- 7 - 3

x^{2} = \frac{1}{3}

- 5 y^{2} + 8 y + 8 \geq 8 y + 3

What are the solutions to the equation 1.87=4.9t^2 ?
The solutions to the equation 1.87=4.9t^2 are t=(sqrt(187))/(7sqrt(10)),t=-(sqrt(187))/(7sqrt(10))
Find the zeros of 1.87=4.9t^2
The zeros of 1.87=4.9t^2 are t=(sqrt(187))/(7sqrt(10)),t=-(sqrt(187))/(7sqrt(10))