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What are the solutions to the equation 1.87=4.9t^2 ?
The solutions to the equation 1.87=4.9t^2 are t=(sqrt(187))/(7sqrt(10)),t=-(sqrt(187))/(7sqrt(10))Find the zeros of 1.87=4.9t^2
The zeros of 1.87=4.9t^2 are t=(sqrt(187))/(7sqrt(10)),t=-(sqrt(187))/(7sqrt(10))