What are the solutions to the equation 3x^2+13x-10=0 ?

The solutions to the equation 3x^2+13x-10=0 are x= 2/3 ,x=-5

Find the zeros of 3x^2+13x-10=0

The zeros of 3x^2+13x-10=0 are x= 2/3 ,x=-5

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3 x^{2} + 13 x - 10 = 0

x = \frac{2}{3}, x = - 5

Decimal Notation

x = 0.66666 \dots, x = - 5

Solution steps

3 x^{2} + 13 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 (- 10) = 17

x_{1, 2} = \frac{- 13 \pm 17}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 13 + 17}{2 \cdot 3}, x_{2} = \frac{- 13 - 17}{2 \cdot 3}

x = \frac{- 13 + 17}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 13 - 17}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 5

(x - 5)^{2} = - 36

\frac{2}{3} x - \frac{5}{4} = - \frac{5}{6} x + \frac{7}{6}

6 x \geq 2 x - 8

1.05 > \frac{1 + 10 w ^{2}}{1 + w ^{2}}

\frac{9 ( - 3 )}{∣ 9 ( - 3 ) ∣}

What are the solutions to the equation 3x^2+13x-10=0 ?
The solutions to the equation 3x^2+13x-10=0 are x= 2/3 ,x=-5
Find the zeros of 3x^2+13x-10=0
The zeros of 3x^2+13x-10=0 are x= 2/3 ,x=-5