What is the answer to x+1/3 [x-3-1/2 (4-3x)]=0 ?

The answer to x+1/3 [x-3-1/2 (4-3x)]=0 is x= 10/11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+1/3 [x-3-1/2 (4-3x)]=0

x + \frac{1}{3} [x - 3 - \frac{1}{2} (4 - 3 x)] = 0

x = \frac{10}{11}

Decimal Notation

x = 0.90909 \dots

Solution steps

x + \frac{1}{3} [x - 3 - \frac{1}{2} (4 - 3 x)] = 0

\frac{1}{3} (x - 3 - \frac{1}{2} (4 - 3 x)) = \frac{x - 3 - \frac{1}{2} ( 4 - 3 x )}{3}

x + \frac{x - 3 - \frac{1}{2} ( 4 - 3 x )}{3} = 0

Multiply both sides by

3

4 x - 3 - \frac{1}{2} (4 - 3 x) = 0

Expand

4 x - 3 - \frac{1}{2} (4 - 3 x) : \frac{11 x}{2} - 5

\frac{11 x}{2} - 5 = 0

Multiply both sides by

2

11 x - 10 = 0

Move

10

to the right side

11 x = 10

Divide both sides by

11

x = \frac{10}{11}

∣ 2 x - 7 ∣ \leq 11

3 x - 4 - 5 x = x + 4 + x

(x + h)^{2}

11 - m = 51 - 6 m

\frac{4}{8} \frac{2}{5}

What is the answer to x+1/3 [x-3-1/2 (4-3x)]=0 ?
The answer to x+1/3 [x-3-1/2 (4-3x)]=0 is x= 10/11
Solve for x: x+1/3 [x-3-1/2 (4-3x)]=0
The solution is x= 10/11