What are the solutions to the equation x^2+2x-1=0 ?

The solutions to the equation x^2+2x-1=0 are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of x^2+2x-1=0

The zeros of x^2+2x-1=0 are x=-1+sqrt(2),x=-1-sqrt(2)

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x^{2} + 2 x - 1 = 0

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

x = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

x = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

7 w > - 49

\frac{2}{3} x - 4 = \frac{5}{6}

12 x^{2} - 27 y^{2}

x^{2} - 7 x y + 12 y^{2}

2 (6 b + 8) = 4 + 6 b

What are the solutions to the equation x^2+2x-1=0 ?
The solutions to the equation x^2+2x-1=0 are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of x^2+2x-1=0
The zeros of x^2+2x-1=0 are x=-1+sqrt(2),x=-1-sqrt(2)