What are the solutions to the equation 0.12x^2-0.2x=0.11 ?

The solutions to the equation 0.12x^2-0.2x=0.11 are x=(5+sqrt(58))/6 ,x=(5-sqrt(58))/6

Find the zeros of 0.12x^2-0.2x=0.11

The zeros of 0.12x^2-0.2x=0.11 are x=(5+sqrt(58))/6 ,x=(5-sqrt(58))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.12 x^{2} - 0.2 x = 0.11

x = \frac{5 + 58}{6}, x = \frac{5 - 58}{6}

Decimal Notation

x = 2.10262 \dots, x = - 0.43596 \dots

Solution steps

0.12 x^{2} - 0.2 x = 0.11

Multiply both sides by

100

12 x^{2} - 20 x = 11

Move

11

to the left side

12 x^{2} - 20 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 12 ( - 11 )}{2 \cdot 12}

(- 20)^{2} - 4 \cdot 12 (- 11) = 458

x_{1, 2} = \frac{- ( - 20 ) \pm 4 58}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 58}{2 \cdot 12}, x_{2} = \frac{- ( - 20 ) - 4 58}{2 \cdot 12}

x = \frac{- ( - 20 ) + 4 58}{2 \cdot 12} : \frac{5 + 58}{6}

x = \frac{- ( - 20 ) - 4 58}{2 \cdot 12} : \frac{5 - 58}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 58}{6}, x = \frac{5 - 58}{6}

28 + 20 x

980 \cdot \frac{1}{7}

5 x^{2} + 8 x < 4

(x^{3})^{4}

(\frac{( - 2 x ) ^{2}}{3 x y ^{2}})^{3}

What are the solutions to the equation 0.12x^2-0.2x=0.11 ?
The solutions to the equation 0.12x^2-0.2x=0.11 are x=(5+sqrt(58))/6 ,x=(5-sqrt(58))/6
Find the zeros of 0.12x^2-0.2x=0.11
The zeros of 0.12x^2-0.2x=0.11 are x=(5+sqrt(58))/6 ,x=(5-sqrt(58))/6