What are the solutions to the equation x^2-x+8=0 ?

The solutions to the equation x^2-x+8=0 are x= 1/2+i(sqrt(31))/2 ,x= 1/2-i(sqrt(31))/2

Find the zeros of x^2-x+8=0

The zeros of x^2-x+8=0 are x= 1/2+i(sqrt(31))/2 ,x= 1/2-i(sqrt(31))/2

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x^{2} - x + 8 = 0

x = \frac{1}{2} + i \frac{31}{2}, x = \frac{1}{2} - i \frac{31}{2}

Solution steps

x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 8 : 31 i

x_{1, 2} = \frac{- ( - 1 ) \pm 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 31 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 31 i}{2 \cdot 1} : \frac{1}{2} + i \frac{31}{2}

x = \frac{- ( - 1 ) - 31 i}{2 \cdot 1} : \frac{1}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{31}{2}, x = \frac{1}{2} - i \frac{31}{2}

x^{\frac{5}{2}} - 81 x^{\frac{1}{2}}

\frac{2}{3} + \frac{a}{7}

- 7 y = - 77

6 x = - 12

\frac{9}{10 k ^{4}} \cdot \frac{2 k ^{4}}{3}

What are the solutions to the equation x^2-x+8=0 ?
The solutions to the equation x^2-x+8=0 are x= 1/2+i(sqrt(31))/2 ,x= 1/2-i(sqrt(31))/2
Find the zeros of x^2-x+8=0
The zeros of x^2-x+8=0 are x= 1/2+i(sqrt(31))/2 ,x= 1/2-i(sqrt(31))/2