What are the solutions to the equation x^2+2x+21=0 ?

The solutions to the equation x^2+2x+21=0 are x=-1+2sqrt(5)i,x=-1-2sqrt(5)i

Find the zeros of x^2+2x+21=0

The zeros of x^2+2x+21=0 are x=-1+2sqrt(5)i,x=-1-2sqrt(5)i

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x^{2} + 2 x + 21 = 0

x = - 1 + 25 i, x = - 1 - 25 i

Solution steps

x^{2} + 2 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 21 : 45 i

x_{1, 2} = \frac{- 2 \pm 4 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 5 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 5 i}{2 \cdot 1}

x = \frac{- 2 + 4 5 i}{2 \cdot 1} : - 1 + 25 i

x = \frac{- 2 - 4 5 i}{2 \cdot 1} : - 1 - 25 i

The solutions to the quadratic equation are:

x = - 1 + 25 i, x = - 1 - 25 i

\frac{x}{4} = 10

4 = 3 (2 x + 1) - 11

x^{2} - 8 x - 7 x = 4

3 x - 2 + 3 - 6 x = 2 - 2 x + 2

v^{2} - 25

What are the solutions to the equation x^2+2x+21=0 ?
The solutions to the equation x^2+2x+21=0 are x=-1+2sqrt(5)i,x=-1-2sqrt(5)i
Find the zeros of x^2+2x+21=0
The zeros of x^2+2x+21=0 are x=-1+2sqrt(5)i,x=-1-2sqrt(5)i