What are the solutions to the equation x^2+4x=3 ?

The solutions to the equation x^2+4x=3 are x=-2+sqrt(7),x=-2-sqrt(7)

Find the zeros of x^2+4x=3

The zeros of x^2+4x=3 are x=-2+sqrt(7),x=-2-sqrt(7)

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x^{2} + 4 x = 3

x = - 2 + 7, x = - 2 - 7

Decimal Notation

x = 0.64575 \dots, x = - 4.64575 \dots

Solution steps

x^{2} + 4 x = 3

Move

3

to the left side

x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

x = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

x = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

x = - 2 + 7, x = - 2 - 7

a^{3} - 3 + 3 a^{2} - a

y^{2} + 8 y - 2 = 0

13 x^{2} - 38 x - 3

3 0^{\circ} \cdot \frac{π}{18 0 ^{\circ}}

4 x^{2} + 36 x + 81 = 0

What are the solutions to the equation x^2+4x=3 ?
The solutions to the equation x^2+4x=3 are x=-2+sqrt(7),x=-2-sqrt(7)
Find the zeros of x^2+4x=3
The zeros of x^2+4x=3 are x=-2+sqrt(7),x=-2-sqrt(7)