What are the solutions to the equation 4x^2-16x+9=0 ?

The solutions to the equation 4x^2-16x+9=0 are x=(4+sqrt(7))/2 ,x=(4-sqrt(7))/2

Find the zeros of 4x^2-16x+9=0

The zeros of 4x^2-16x+9=0 are x=(4+sqrt(7))/2 ,x=(4-sqrt(7))/2

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4 x^{2} - 16 x + 9 = 0

x = \frac{4 + 7}{2}, x = \frac{4 - 7}{2}

Solution steps

4 x^{2} - 16 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 9 = 47

x_{1, 2} = \frac{- ( - 16 ) \pm 4 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 7}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 4 7}{2 \cdot 4}

x = \frac{- ( - 16 ) + 4 7}{2 \cdot 4} : \frac{4 + 7}{2}

x = \frac{- ( - 16 ) - 4 7}{2 \cdot 4} : \frac{4 - 7}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 7}{2}, x = \frac{4 - 7}{2}

\frac{4 ( 0.36 )}{20 ( 1 - 7 e ^{- 6} )}

(5 x^{5})^{2}

3 = \frac{g}{4} - 5

132

34 a x^{2} + 51 a^{2} y - 68 a y^{2}

What are the solutions to the equation 4x^2-16x+9=0 ?
The solutions to the equation 4x^2-16x+9=0 are x=(4+sqrt(7))/2 ,x=(4-sqrt(7))/2
Find the zeros of 4x^2-16x+9=0
The zeros of 4x^2-16x+9=0 are x=(4+sqrt(7))/2 ,x=(4-sqrt(7))/2