What are the solutions to the equation 6r^2+r-2=0 ?

The solutions to the equation 6r^2+r-2=0 are r= 1/2 ,r=-2/3

Find the zeros of 6r^2+r-2=0

The zeros of 6r^2+r-2=0 are r= 1/2 ,r=-2/3

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6 r^{2} + r - 2 = 0

r = \frac{1}{2}, r = - \frac{2}{3}

Decimal Notation

r = 0.5, r = - 0.66666 \dots

Solution steps

6 r^{2} + r - 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 2) = 7

r_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 6}

Separate the solutions

r_{1} = \frac{- 1 + 7}{2 \cdot 6}, r_{2} = \frac{- 1 - 7}{2 \cdot 6}

r = \frac{- 1 + 7}{2 \cdot 6} : \frac{1}{2}

r = \frac{- 1 - 7}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

r = \frac{1}{2}, r = - \frac{2}{3}

3 x^{3} + 4 x^{2} - x - 2

- x^{2} + 10 x + 9 = 0

10.36 + 0.131 \cdot 12 + 0.21 \cdot 12

- (x - 4) + 8 x - 7 - 2 (x - 2) = - 8 x - 5 (7 - x) + 2 x

26 = x

What are the solutions to the equation 6r^2+r-2=0 ?
The solutions to the equation 6r^2+r-2=0 are r= 1/2 ,r=-2/3
Find the zeros of 6r^2+r-2=0
The zeros of 6r^2+r-2=0 are r= 1/2 ,r=-2/3