What is 2(1/2+3/2 i)^2-2(1/2+3/2 i)+5 ?

The solution to 2(1/2+3/2 i)^2-2(1/2+3/2 i)+5 is 0

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simplify 2(1/2+3/2 i)^2-2(1/2+3/2 i)+5

simplify

2 (\frac{1}{2} + \frac{3}{2} i)^{2} - 2 (\frac{1}{2} + \frac{3}{2} i) + 5

0

Solution steps

2 (\frac{1}{2} + \frac{3}{2} i)^{2} - 2 (\frac{1}{2} + \frac{3}{2} i) + 5

(\frac{1}{2} + \frac{3}{2} i)^{2} = \frac{3 i - 4}{2}

\frac{1}{2} + \frac{3}{2} i = \frac{3 i + 1}{2}

= 2 \cdot \frac{3 i - 4}{2} - 2 \cdot \frac{3 i + 1}{2} + 5

2 \cdot \frac{3 i - 4}{2} = 3 i - 4

2 \cdot \frac{3 i + 1}{2} = 3 i + 1

= 3 i - 4 - (3 i + 1) + 5

Group like terms

= 3 i - (3 i + 1) - 4 + 5

Add the numbers:

- 4 + 5 = 1

= 3 i - (3 i + 1) + 1

Simplify

- (3 i + 1) : - 1 - 3 i

= 3 i - 1 - 3 i + 1

Group like terms

= 3 i - 3 i - 1 + 1

Add similar elements:

3 i - 3 i = 0

= - 1 + 1

Add the numbers:

- 1 + 1 = 0

= 0

z = 3 (11) + 5 (0)

0.1 a = 0.01 a

\frac{2 x + 5}{3} - \frac{x + 1}{9} = \frac{5 x + 3}{4}

- ∣ 3 + 3 x ∣ - 7 \leq - 16

4 x^{3} - x^{2} - 64 x + 16

What is 2(1/2+3/2 i)^2-2(1/2+3/2 i)+5 ?
The solution to 2(1/2+3/2 i)^2-2(1/2+3/2 i)+5 is 0