What are the solutions to the equation 14b^2-2=-3b ?

The solutions to the equation 14b^2-2=-3b are b= 2/7 ,b=-1/2

Find the zeros of 14b^2-2=-3b

The zeros of 14b^2-2=-3b are b= 2/7 ,b=-1/2

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14 b^{2} - 2 = - 3 b

b = \frac{2}{7}, b = - \frac{1}{2}

Decimal Notation

b = 0.28571 \dots, b = - 0.5

Solution steps

14 b^{2} - 2 = - 3 b

Move

3 b

to the left side

14 b^{2} - 2 + 3 b = 0

Write in the standard form

a x^{2} + b x + c = 0

14 b^{2} + 3 b - 2 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 14 ( - 2 )}{2 \cdot 14}

3^{2} - 4 \cdot 14 (- 2) = 11

b_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 14}

Separate the solutions

b_{1} = \frac{- 3 + 11}{2 \cdot 14}, b_{2} = \frac{- 3 - 11}{2 \cdot 14}

b = \frac{- 3 + 11}{2 \cdot 14} : \frac{2}{7}

b = \frac{- 3 - 11}{2 \cdot 14} : - \frac{1}{2}

The solutions to the quadratic equation are:

b = \frac{2}{7}, b = - \frac{1}{2}

4 x^{3} - 32 y^{3}

r^{3} - 7 r - 6

(1/5 + 1/5) - (4/3 + 3/4)

66

6 - 2 x = 28

What are the solutions to the equation 14b^2-2=-3b ?
The solutions to the equation 14b^2-2=-3b are b= 2/7 ,b=-1/2
Find the zeros of 14b^2-2=-3b
The zeros of 14b^2-2=-3b are b= 2/7 ,b=-1/2