What are the solutions to the equation a^2+3a=a+63 ?

The solutions to the equation a^2+3a=a+63 are a=7,a=-9

Find the zeros of a^2+3a=a+63

The zeros of a^2+3a=a+63 are a=7,a=-9

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a^{2} + 3 a = a + 63

a = 7, a = - 9

Solution steps

a^{2} + 3 a = a + 63

Move

63

to the left side

a^{2} + 3 a - 63 = a

Move

a

to the left side

a^{2} + 2 a - 63 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 63) = 16

a_{1, 2} = \frac{- 2 \pm 16}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 16}{2 \cdot 1}, a_{2} = \frac{- 2 - 16}{2 \cdot 1}

a = \frac{- 2 + 16}{2 \cdot 1} : 7

a = \frac{- 2 - 16}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

a = 7, a = - 9

(5^{2})^{3}

- 6 x^{3} + 3 x^{2} + 84 x

4 x^{2} = 2.166667

7 n - 4 n - 6 = 12

((- \frac{2}{6})^{- 4})^{2}

What are the solutions to the equation a^2+3a=a+63 ?
The solutions to the equation a^2+3a=a+63 are a=7,a=-9
Find the zeros of a^2+3a=a+63
The zeros of a^2+3a=a+63 are a=7,a=-9