What are the solutions to the equation 0=(x-2)^2-7 ?

The solutions to the equation 0=(x-2)^2-7 are x=sqrt(7)+2,x=-sqrt(7)+2

Find the zeros of 0=(x-2)^2-7

The zeros of 0=(x-2)^2-7 are x=sqrt(7)+2,x=-sqrt(7)+2

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0 = (x - 2)^{2} - 7

x = 7 + 2, x = - 7 + 2

Solution steps

0 = (x - 2)^{2} - 7

Switch sides

(x - 2)^{2} - 7 = 0

Move

7

to the right side

(x - 2)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 7 : x = 7 + 2

Solve

x - 2 = - 7 : x = - 7 + 2

The solutions to the quadratic equation are:

x = 7 + 2, x = - 7 + 2

3 (2 w - 7) = 3

x^{3} + x^{5} - x^{7}

x^{3} + 4 x^{2} + x - 6

8 (p + 5) = 24

(w + 1)^{2} - 48 = 0

What are the solutions to the equation 0=(x-2)^2-7 ?
The solutions to the equation 0=(x-2)^2-7 are x=sqrt(7)+2,x=-sqrt(7)+2
Find the zeros of 0=(x-2)^2-7
The zeros of 0=(x-2)^2-7 are x=sqrt(7)+2,x=-sqrt(7)+2