What are the solutions to the equation 1^2+x^2=7^2 ?

The solutions to the equation 1^2+x^2=7^2 are x=4sqrt(3),x=-4sqrt(3)

Find the zeros of 1^2+x^2=7^2

The zeros of 1^2+x^2=7^2 are x=4sqrt(3),x=-4sqrt(3)

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1^{2} + x^{2} = 7^{2}

x = 43, x = - 43

Decimal Notation

x = 6.92820 \dots, x = - 6.92820 \dots

Solution steps

1^{2} + x^{2} = 7^{2}

Move

1^{2}

to the right side

x^{2} = 48

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 48, x = - 48

48 = 43

- 48 = - 43

x = 43, x = - 43

- 3 x + 4 \leq 13

j^{2} - j = 9

7 + 4 ∣ 1 - 5 x ∣ = 47

- 0.7 + \frac{2}{8}

What are the solutions to the equation 1^2+x^2=7^2 ?
The solutions to the equation 1^2+x^2=7^2 are x=4sqrt(3),x=-4sqrt(3)
Find the zeros of 1^2+x^2=7^2
The zeros of 1^2+x^2=7^2 are x=4sqrt(3),x=-4sqrt(3)