What is the answer to d=sqrt((3-7)^2+(2-6)^2) ?

The answer to d=sqrt((3-7)^2+(2-6)^2) is d=4sqrt(2)

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d=sqrt((3-7)^2+(2-6)^2)

d = (3 - 7)^{2} + (2 - 6)^{2}

d = 42

Decimal Notation

d = 5.65685 \dots

Solution steps

d = (3 - 7)^{2} + (2 - 6)^{2}

Simplify

(3 - 7)^{2} + (2 - 6)^{2} : 42

d = 42

3 x^{3} - 81

(- 10)^{3}

3 x + 0 = 12

(2 x)^{3}

\frac{\frac{20}{21}}{\frac{15}{28}}

What is the answer to d=sqrt((3-7)^2+(2-6)^2) ?
The answer to d=sqrt((3-7)^2+(2-6)^2) is d=4sqrt(2)
Solve for d: d=sqrt((3-7)^2+(2-6)^2)
The solution is d=4sqrt(2)